Algo Infinity Verse

Master the Paths of Binary Tree Traversal Depth-First (DFS), Breadth-First (BFS) & Recursion

|
0 Core Topics
0 Practice Checks
0 Interactive Quiz
Your Progress: 0/8 Topics Completed
01

Introduction to Tree Traversals

A Binary Tree is a hierarchical, non-linear data structure where each node has at most two children, referred to as the left child and the right child. Unlike linear structures (arrays, linked lists) which have a single logical way to iterate, trees can be traversed in several different ways.

Tree Traversal is the process of visiting every node in the tree exactly once. Traversals are generally divided into two main categories:

  • Depth-First Search (DFS): Recursively explores paths as deep as possible before backtracking. Includes: Preorder, Inorder, and Postorder traversals.
  • Breadth-First Search (BFS): Visits nodes level-by-level, starting from the root. Includes: Level-Order traversal.
Practice: Traversal Styles

Which category of traversal visits all nodes on level 1 before visiting nodes on level 2?

Answer: Breadth-First Search (BFS) / Level-Order Traversal

Explanation: BFS processes nodes layer-by-layer (level-by-level), whereas DFS goes down a single path to a leaf node before returning to process other sibling branches.

02

Preorder Traversal (Root → Left → Right)

In Preorder Traversal, the node is processed before (pre) traversing its left and right subtrees.

Steps of Preorder Traversal

  1. Visit the Root node.
  2. Recursively traverse the Left subtree.
  3. Recursively traverse the Right subtree.

Preorder traversal is commonly used to create a copy of the tree or to serialize a expression tree structure into prefix notation.

Pseudocode (Recursive)
function preorder(Node root)
    if root is null then return
    
    visit(root)
    preorder(root.left)
    preorder(root.right)
end function
Practice: Preorder Trace

For a tree with root node `A`, left child `B`, and right child `C`, what is the Preorder traversal order?

Answer: A → B → C

Explanation: Preorder visits the root (`A`), then traverses the left subtree (`B`), and then the right subtree (`C`).

03

Inorder Traversal (Left → Root → Right)

In Inorder Traversal, the node is processed in-between (in) traversing its left and right subtrees.

Steps of Inorder Traversal

  1. Recursively traverse the Left subtree.
  2. Visit the Root node.
  3. Recursively traverse the Right subtree.

In a Binary Search Tree (BST), executing an inorder traversal visits the nodes in **strictly ascending sorted order**. This is one of the most useful properties of BSTs.

Pseudocode (Recursive)
function inorder(Node root)
    if root is null then return
    
    inorder(root.left)
    visit(root)
    inorder(root.right)
end function
Practice: Inorder Sorted

True or False: Performing an Inorder traversal on any binary tree always yields a sorted sequence of keys.

Answer: False

Explanation: This sorting property is exclusive to Binary Search Trees (BSTs), where left keys are smaller than root, and right keys are larger. It does not apply to general binary trees.

04

Postorder Traversal (Left → Right → Root)

In Postorder Traversal, the node is processed after (post) traversing both its left and right subtrees.

Steps of Postorder Traversal

  1. Recursively traverse the Left subtree.
  2. Recursively traverse the Right subtree.
  3. Visit the Root node.

Postorder traversal is commonly used in deleting/freeing a tree (since you must delete children before deleting the parent) or for calculating the size/height of subtrees bottom-up.

Pseudocode (Recursive)
function postorder(Node root)
    if root is null then return
    
    postorder(root.left)
    postorder(root.right)
    visit(root)
end function
Practice: Deletion Usage

Why is postorder traversal preferred when deleting a tree from memory?

Answer: Bottom-up deletion

Explanation: If you delete the root node first (preorder), you lose references to the left and right children, causing memory leaks. Postorder ensures children are freed before parent nodes.

05

Level-Order Traversal (Breadth-First Search)

Level-Order Traversal processes tree nodes layer-by-layer (horizontally), starting from level 0 (root), then level 1, and so on.

Since recursion uses a call stack (which behaves in a Depth-First manner), Level-Order traversal must be implemented iteratively using a **Queue data structure** (First-In, First-Out).

Queue-Based BFS Steps

  1. Create an empty queue and enqueue the **Root** node.
  2. Loop while the queue is not empty:
    • Dequeue a node and visit/process it.
    • Enqueue the dequeued node's **Left child** (if exists).
    • Enqueue the dequeued node's **Right child** (if exists).
Pseudocode (Iterative Queue)
function levelOrder(Node root)
    if root is null then return
    
    Queue q = new Queue()
    q.enqueue(root)
    
    while q is not empty
        Node curr = q.dequeue()
        visit(curr)
        
        if curr.left is not null then
            q.enqueue(curr.left)
        end if
        if curr.right is not null then
            q.enqueue(curr.right)
        end if
    end while
end function
Practice: Data Structure

Which data structure is essential to perform Level-Order traversal iteratively?

Answer: Queue (FIFO)

Explanation: A Queue ensures that nodes are processed in the order they are discovered, yielding a level-by-level breadth-first visit pattern.

06

Tracing Traversal Paths

Below is a visual binary tree. Use it to trace the different path structures:

1 2 3 4 5

Traces of the Above Tree:

  • Preorder (Root-L-R): 1 → 2 → 4 → 5 → 3
  • Inorder (L-Root-R): 4 → 2 → 5 → 1 → 3
  • Postorder (L-R-Root): 4 → 5 → 2 → 3 → 1
  • Level-Order (BFS): 1 → 2 → 3 → 4 → 5
Practice: Tree Tracing

In Inorder traversal of the diagrammed tree above, which node is visited immediately after node `5`?

Answer: 1

Explanation: Inorder visits left branch of 1 first (which traces `4 → 2 → 5`). Once the left branch is complete, it backtracks and processes the root node, which is `1`.

07

Comprehensive Exercises

Analyze the binary trees described in the scenarios below to solve the traversal outputs.

Exercise 1: Reconstructing Trees

Scenario: You are given the Preorder traversal [A, B, D, E, C] and Inorder traversal [D, B, E, A, C]. Reconstruct the tree and identify the root's right child.

Solution: Node C

Explanation: The first node in preorder is always the root, which is `A`. Looking at the inorder traversal, elements to the left of `A` (`D, B, E`) are in the left subtree, and elements to the right (`C`) are in the right subtree. Thus, `C` is the right child of the root.

Exercise 2: Binary Search Tree Property

Scenario: A Binary Search Tree is created by inserting the keys [15, 10, 20, 8, 12]. What sequence is output by performing an Inorder traversal?

Solution: 8 → 10 → 12 → 15 → 20

Explanation: Inorder traversal on any valid BST always yields a sorted sequence of values in ascending order.

08

Quiz & Knowledge Check

Test your understanding of Binary Tree traversals:

Q1. An inorder traversal executed on a BST always returns keys in what arrangement?
Explanation: Inorder traversal visits left-root-right. By definition of a BST, all left child keys are smaller than root, and right keys are larger, yielding sorted output.
Q2. In preorder traversal, which node in any subtree is processed first?
Explanation: Preorder visits root first, then left subtree, then right subtree (Root-Left-Right).
Q3. What is the traversal sequence rule for Postorder?
Explanation: Postorder processes children subtrees before the root node, following Left → Right → Root (LRD).
Q4. What helper data structure is required to perform Level-Order traversal iteratively?
Explanation: Level-order (BFS) requires a Queue to process nodes in FIFO order level-by-level.
Q5. Which DFS traversal style processes the root node of the entire tree last?
Explanation: Postorder visits Left, then Right, and processes Root last (Left → Right → Root).
Quiz Results
You scored 0 / 5